Write the solution set of the equation ${x^2} + x - 2 = 0$ in roster form.
Write the solution set of the equation ${x^2} + x - 2 = 0$ in roster form.
The given equation can be written as
$\left( {x - 1} \right)\left( {x - 2} \right) = 0,$ i.e., $x=1,-2 $
Therefore, the solution set of the given equation can be written in roster form as $\{ 1, - 2\} $
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- [JEE MAIN 2021]
Match each of the set on the left described in the roster form with the same set on the right described in the set-builder form:
$(i)$ $\{ P,R,I,N,C,A,L\} $
$(a)$ $\{ x:x$ is a positive integer and is adivisor of $18\} $
$(ii)$ $\{ \,0\,\} $
$(b)$ $\{ x:x$ is an integer and ${x^2} - 9 = 0\} $
$(iii)$ $\{ 1,2,3,6,9,18\} $
$(c)$ $\{ x:x$ is an integer and $x + 1 = 1\} $
$(iv)$ $\{ 3, - 3\} $
$(d)$ $\{ x:x$ is aletter of the word $PRINCIPAL\} $
Match each of the set on the left described in the roster form with the same set on the right described in the set-builder form:
| $(i)$ $\{ P,R,I,N,C,A,L\} $ | $(a)$ $\{ x:x$ is a positive integer and is adivisor of $18\} $ |
| $(ii)$ $\{ \,0\,\} $ | $(b)$ $\{ x:x$ is an integer and ${x^2} - 9 = 0\} $ |
| $(iii)$ $\{ 1,2,3,6,9,18\} $ | $(c)$ $\{ x:x$ is an integer and $x + 1 = 1\} $ |
| $(iv)$ $\{ 3, - 3\} $ | $(d)$ $\{ x:x$ is aletter of the word $PRINCIPAL\} $ |
Let $A=\{1,2,3,4,5,6\} .$ Insert the appropriate symbol $\in$ or $\notin$ in the blank spaces:
$10 \, .........\, A $
Let $A=\{1,2,3,4,5,6\} .$ Insert the appropriate symbol $\in$ or $\notin$ in the blank spaces:
$10 \, .........\, A $